@Atilla, Try searching on the U.K. Amazon for the same description. It may just be a separate website / link / product problem.
@Dreamweaver The Rfid bit is only 5-6 dollars more, and it’ll probably be towards the end anyways.
You are right! 
£35, free delivery
That is cheap for all you get.
I just love the Full Metal Jacket quote in the last answer 
You risk the ire of the thought police my friend.
Sadly that’s uncommon and thus very identifying info.
Not sure, but you are a very active user. And you are Rosco. I guess you can be cross linked pretty easily.
I try to act like I’m certain future social credit systems will find this account and link it with me.
I write so much here, I don’t think it’s hard to find me if you have 2 of my accounts on different platforms.
I poison the well in other ways. I’m very aware that a silent user sticks out like a sore thumb in this day and age.
That’s what comes with living on the edge 
Yes I would like to participate because I don’t know very well chips
I’m starting to put a plan together then. It’ll be the end of next week before I have anything to show for it. Just FYI.
Id like to volunteer to learn more honestly scared of college degree and such lol so a tutorial class is great how do I join
You just did. Stay tuned. Will have more specifics late next week / weekend.
Sign me up for sure! Have a bunch of electronics on hand and would love to use them a bit more haha
I would like to join in, but since i’m a minor without any funds, I cannot sorry. If there are any resources you could point me torwards to emulate an arduino and program it, please say so.
Yeah, I’m looking at a 30 dollar plan A, and a free plan B. I really think you’ll learn more from being hands on with plan A, but I get that people can’t always drop cash on stuff.
depending on when you do this, I may be able to do plan A. I usually get a bit of money for christmas and doing odd jobs for family around that time, but plan b is probbably what i will have to do.
okay lads I need some help with this code. It is meant to find the factors of a number and if it’s prime just say it’s prime. For some reason it’ll try to spit out both (ignore indentation the paste messed the up)
def print_factors(x):
print(“The factors of”,x,“are:”)
for i in range(1, x + 1):
if x % i == 0:
print(i)
def find_prime(y):
if y > 1:
for i in range(2,y):
if (y % i) == 0:
print_factors(y)
elif:
print(“The number”,y,“is prime!”)
y=int(input(“Enter a number:”))
find_prime(y)
your logic here is funky. you have the print statement for the prime status in an “elif” block (which I assume is supposed to be an else block, since an empty elif like that should throw a compiler error). However, that conditional block is based off the previous if statement. Ie, if that condition (y%1==0) returns false, then it will automatically try to say that the number is prime.
What you want to do is have the function stop running once you find a factor, and if it doesn’t find a factor by the time the loop ends, then you print the prime statement.
Also, for future reference, if you highlight your code and click this button in the post toolbar, it will format it as code and let you keep spacing:
